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2r^2+12r+48=-4
We move all terms to the left:
2r^2+12r+48-(-4)=0
We add all the numbers together, and all the variables
2r^2+12r+52=0
a = 2; b = 12; c = +52;
Δ = b2-4ac
Δ = 122-4·2·52
Δ = -272
Delta is less than zero, so there is no solution for the equation
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